수다닷컴

질문 제목 : 소스를 짜놓았는데요
무조건 5개 두는걸 만들었느데
이제 수비를 만들껀데
적이 3개두면 막는걸 어떻게 만들죠?
mc가 제가둔돌 ec가 적이둔돌
ec를 사용하라는데 어떻게만들어야하나요..ㅠ질문 내용 :
#include stdafx.h
#include stdlib.h
#define true 1
#define false 0
#define maxxy 16
#define black 1
#define white 0
#define empty -1
#define outbd -2
#define ncell maxxy
extern int b(int x, int y, int def=-2);
#define myfunction f201202037
void myfunction(int *newx, int *newy, int mc, int curturn)
{
int ec = mc == white ? black : white;
int x[4] = {1,1,0,-1};
int y[4] = {0,1,1,1};
int iy, ix ,d;
for (iy = 0; iy maxxy; iy++) {
for (ix = 0; ix maxxy; ix++) {
for( d = 0 ; d 4 ; d++) {
if (b(ix,iy) == mc && b(ix+1*x[d],iy+1*y[d]) == mc && b(ix+2*x[d],iy+2*y[d]) == mc && b(ix+3*x[d],iy+3*y[d]) == mc && b(ix+4*x[d],iy+4*y[d]) == empty) {
*newx = ix + 4*x[d];
*newy = iy + 4*y[d];
return;
}
}
}
}

for (iy = 0; iy maxxy; iy++) {
for (ix = 0; ix maxxy; ix++) {
for( d = 0 ; d 4 ; d++) {
if (b(ix,iy) == mc && b(ix+1*x[d],iy+1*y[d]) == mc && b(ix+2*x[d],iy+2*y[d]) == mc && b(ix+3*x[d],iy+3*y[d]) == empty) {
*newx = ix + 3*x[d];
*newy = iy + 3*y[d];
return;
}
}
}
}

for (iy = 0; iy maxxy; iy++) {
for (ix = 0; ix maxxy; ix++) {
for( d = 0 ; d 4 ; d++) {
if (b(ix,iy) == mc && b(ix+1*x[d],iy+1*y[d]) == mc && b(ix+2*x[d],iy+2*y[d]) == empty) {
*newx = ix + 2*x[d];
*newy = iy + 2*y[d];
return;
}
}
}
}for (iy = 0; iy maxxy; iy++) {
for (ix = 0; ix maxxy; ix++) {
for( d = 0 ; d 4 ; d++) {
if (b(ix,iy) == mc && b(ix+1*x[d],iy+1*y[d]) == empty) {
*newx = ix + 1*x[d];
*newy = iy + 1*y[d];
return;
}
}
}
}
*newx = rand() % maxxy;
*newy = rand() % maxxy;
}

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