수다닷컴

순환소수를 분수로 바꾸는 프로그램입니다입력예)
4 첫쨰줄은 갯수
1.(35) 괄호친부분이 순환하는 부분
0.(5)
0.7(145)
2.3(42) 출력 예)
134/99
5/9
3569/4995
773/330 #include stdio.h
#include stdlib.h#define max 20void input();
void round();
void output();int n;
int a[max]; //정수
int b[max][max]; //소수점아래
int downnum[max][max]; //소수
int roop[max][max]; //순환부분
int temp, cnt[max], cot[max];
int right=0, left=0, count=1, counts=1;void main()
{
input();
round();
}void input()
{
FILE* si=fopen(input.txt, r);
int i, j, k, mem;
fscanf(si, %d, &n);
for(i=0; in; i++) {
fscanf(si, %d, &a[i]);
for(j=0; j7; j++) {
fscanf(si, %c, &b[i][j]);
if(b[i][j]==41) break;
}
}
for(i=0; in; i++) {
for(j=0; jn; j++) {
if(b[i][j]==40)
{
for(k=0; kj; k++)
{
if(b[i][j]==46) continue;
downnum[i][k]=b[i][k]-48;
cnt[i]++;
}
mem=k+1;
}
if(b[i][j]==41)
{
for(k=mem; kj; k++) {
roop[i][k]=b[i][k]-48;
cnt[i]++;
cot[i]++;
}
}
}
}
}void round()
{
int i, j, k; int ten=1;
for(i=0; icnt[i]; i++) count=count*10;
for(i=0; in; i++) {
left=+a[i]*10;
for(j=0; b[i][j]!=41 && b[i][j]!=40; j++)
{
left+=downnum[i][j]*count;
count=count/10;
temp++;
}
for(j=0; b[i][j]!=41 && b[i][j]!=40; j++)
{
left+=roop[i][j]*count;
count=count/10;
if(count==0) break;
}
for(j=0; jtemp; j++) count=count*10;
left-=a[i]*count;
count=count/10;
for(j=0; b[i][j]!=41 && b[i][j]!=40; j++)
{
left-=downnum[i][j]*count;
count=count/10;
if(count==0) break;
/span }
for(j=0; roop[i][j]!=0; j++) ten=ten*10;
for(j=0; jcot[i]; j++) count=count*10;
for(j=0; jcnt[i]-cot[i]; j++) counts=counts*10;
right=counts-count;
for(i=2; i=9; i++) {
if(right%i==0 && left%2==0)
{
right=right/i;
left=left/i;
}
}
output();
}}void output()
{
FILE* s=fopen(output.txt, w);
fprintf(s, %d/%d\n, right, left);
}대강이렇게짜긴햇는데.. 몬가 아이디어가 부족하네요.. ㅠ. 도움좀요청해요 ㅠ.

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